Discussion Forum



1)

The correct set of four quantum numbers for the valence electrons of rubidium atom(Z=37) is 


A) 5,0,0, $+\frac{1}{2}$

B) 5,1,0, $+\frac{1}{2}$

C) 5,1,1 ,$+\frac{1}{2}$

D) 5,0,1, $+\frac{1}{2}$

Answer:

Option A

Explanation:

Given, atomic number  of Rb, Z=37

 Thus, its elecronic configuration is  [Kr]5s1. Since  the last electron  or valence electron  enter in 5s subshell.

 So, the quantum  numbers are n=5, l=0, (for s orbital) m=0

   $(\because  m=+1 to -1),s=+\frac{1}{2}or -\frac{1}{2}$