Discussion Forum



1)

 In a large building, there are 15 bulbs of 40 W, 5 bulbs of 100W, 5 fans of 80 W and 1 heater of 1 kW. The voltage of the electric mains is 220V. The minimum  capacity of the main fuse of the building will be


A) 8A

B) 10 A

C) 12 A

D) 14 A

Answer:

Option C

Explanation:

 Total power (P) consumed  

                            $=(15\times40)+(5\times100)+(5\times80)+(1\times1000)$

                          =2500W

 As we know,

 power i.e, P=VI

$\Rightarrow $              $ I= \frac{2500}{220}A$

  $= \frac{125}{11}=11.3 A$

                 Minimum capacity should be 12 A