1) From a tower of height H, a particle is thrown vertically upwards with a speed u. The time taken by the particle to hit the ground is n times that taken by it to reach the highest point of its path. The relation between H, u and n is A) 2gH=n2u2 B) gH=(n−2)2u2 C) 2gH=nu2(n−2) D) gH=(n−2)2u2 Answer: Option CExplanation: Time taken to reach the maximum height t1=u/g If t2 is the time taken to hit the ground, i.e, −H=ut2−12gt2 But t2=nt1 [Given] So, −H=unug−12gn2u2g2 −H=nu2g−12n2u2g ⇒ 2gH=nu2(n−2)