Answer:
Option A
Explanation:
Plan This problem can be solved by using concept of oxidant and reductant.
Oxidant increases the oxidation number of the species with which it is reacted.
Reductant decreases the oxidation number of the species with which it is reacted.
H2O2 reacts with KIO4 in the following manner
$Kl^{+7}O_{4}+H_{2}O_{2\rightarrow} Kl^{+5}O_{3}+H_{2}O+O_{2}$
On reaction of KlO4 with H2 O2, Oxidation state of I varies from +7 to +5 i.e,
Thus, KlO4 Thus gets reduced hence H2O2 is a reducing agent here.
-1 +3
$NH_{2}OH+H_{2}O_{2}\rightarrow N_{2}O_{2}+H_{2}O$
In the above reaction, oxidation state of N varies from -1 to +3 Here, oxidation number increases hence H2O2 is acting as an oxidising agent here.
Hence, (a) is the correct choice.
