Answer:
Option D
Explanation:
Plan This problem can be solved by using concept involved in chemical properties of xenon oxide and xenon fluoride
XeF4 on complete hydrolysis produce XeO3
XeO3 on reaction with OH- produces HXeO4- which on further treatment with OH- undergo slow disproportionation reaction and produces XeO64- along with Xe(g) , H2O (l) and O2 (g) as a by-product
OXidation half cell in basic aqueous solution
HXeO−4+5OH−→XeO4−6+3H2O+2e
Reduction half-cell in basic aqueous solution
HXeO−4+3H2O+6e−→Xe+7OH−
Balanced overall disproportionation reaction is
4HXeO−4+8OH−→3XeO4−6+Xe+6H2O
2 products
Complete sequence of reaction can be shown as
XeF6+3H2O→XeO3+3H2F2 OH−→ HXeO−4
OH−/H2O(disproportionation)→XeO4−6(s)+Xe(g)+H2O(l)+O2(g)