Answer:
Option A
Explanation:
Energy corresponding to 248 nm wavelength
$= \frac{1240}{248}eV=5eV$
Energy corresponding to 310 nm wavelength
$= \frac{1240}{310}eV=4eV$
$= \frac{KE_{1}}{KE_{2}}=\frac{\mu_1^2}{\mu_2^2}=\frac{4}{1}$
= $\frac{5eV-W}{4eV-W}$
$\Rightarrow$ $ 16-4W=5-W$
$\Rightarrow$ 11=3W
$\Rightarrow$ $W=\frac{11}{3}=3.67 eV \cong 3.7eV$