Answer:
Option A,D
Explanation:
Plan if a continuous function has values of opposite sign inside an interval, then it has a root in that interval
f,g:[0,1] → R
We take two cases.
Let f and g attain their common maximum value at p
$\Rightarrow$ f(p)=g(p)
where $p\in [0,1]$
Let f and g attain their common maximum value at different points
$\Rightarrow$ f(a)=M and g(b)= M
$\Rightarrow$ f(a)-g(a) >0
and f(b)-g(b) <0
$\Rightarrow$ f(c)-g(c)=0 for some $c \in [0,1]$ as f and g are continuous functions.
$\Rightarrow$ f(c)-g(c)=0 for some $c \in [0,1]$ for all cases. ........(i)
Option
(a) $\Rightarrow$ f2(c)-g2(c)+3[f(c)-g(c)]=0
which is true from Eq.(i).
Option (d) $\Rightarrow$ f2(c)-g2 c)=0 which is true from Eq.(i)
Now, if we take
f(x)=1 and g(x)=1, $\forall x \in [0,1]$
Option (b) and (c) does not hold.
Hence, option (a) and (d) are correct