Answer:
Option A
Explanation:
Applying conservation of angular momentum.
$2mvr-\frac{MR^{2}}{2}\omega=0$
$\omega=\frac{4mvr}{MR^{2}}$
Substituting the values , we get
$\omega=\frac{(4)(5\times 10^{-2})(9)(\frac{1}{4})}{45\times10^{-2}\times\frac{1}{4}}=4 rad/s$