1)

A student is performing an experiment using a resonance column and a tuning fork of frequency  244 s-1. He is told that the air in the tube has been replaced by another gas (assume that the column remains filled with the gas). If the minimum  height at which resonance occurs is   (0.350±0.005) m, the gas in the tube is

(Useful information)

167RT=640J1/2mol1/2

140RT=590J1/2mol1/2. The molar masses M in grams are given in the options. Take the value of 

10/M  for each gas as given there.)


A) Neon (M=20,10/20=7/10)

B) Nitrogen, (M=28,10/28=3/5)

C) Oxygen (M=32,10/32=9/16)

D) Argon (M=36,10/36=17/32)

Answer:

Option D

Explanation:

Minimum  length  =  λ4λ=4l

 Now, v=f ,   λ=(244)×4×l

  as        l=0.350±0.005

    v lies between 336.7 m/s to 346.5 m/s

  Now,   v=γRTM×103  , here M is

 Molecular  mass in gram

                  =100γRT×10M

 For  monoatomic gas 

       γ=1.67

       v=640×10M

For diatomic gas,

      γ=1.4v=590×10M

       VNe=640×710=448m/s

                        VAr=640×1732=340m/s

                           VO2=590×916=331.8m/s

                                  VN2=590×35=354m/s

   only possible answer is Argon