Answer:
Option C
Explanation:
$\frac{Q}{4\pi \epsilon_{0}r_0^2}=\frac{\lambda}{2\pi \epsilon_{0}r_{0}}=\frac{\sigma}{2\epsilon_{0}}$
$Q=2\pi \sigma r_0^2$
(a) is incorrect, $r_{0}=\frac{\lambda}{\pi\sigma}$
(b) is incorrect, $E_{1}(\frac{r_{0}}{2})=4E_{1}(r_{0})$
As, $E_{1}\propto\frac{1}{r^{2}}$
$E_{2}\left(\frac{r_{0}}{2}\right)=2E_{2}(r_{0})$ as $E_{2}\propto\frac{1}{r}$
$\Rightarrow $ (c) is correct.
$E_{3}\left(\frac{r_{0}}{2}\right)=E_{3}(r_{0})=E_{2}(r_{0}) $
as $E_{3}\propto r^{0}$
$\Rightarrow $ (d) is in correct.