Answer:
Option D
Explanation:
If initially all marks were x1, then
$\sigma^{2}_{1}=\frac{\sum(x_{i}-\overline{x})^{2}}{N}$
Now, each is increased by 10
$\therefore$ $\sigma^{2}_{1}=\frac{\sum(x_{i}+10)-(\overline{x}+10))^{2}}{N}=\sigma^{2}_{1}$
So, variance will not change whereas mean, median and mode will increase by 10