Discussion Forum

A ray of light along  $x+\sqrt{3}y=\sqrt{3}$  gets reflected upon reaching x-axis , the equation of the reflected ray is

Answer:

Explanation:

Take any point B(0,1) on gives line, equation of AB'

 $y-0= \frac{-1-0}{0-\sqrt{3}}(x-\sqrt{3})$

$\Rightarrow$     $-\sqrt{3}y=-x+\sqrt{3}$

 $\Rightarrow$     $x-\sqrt{3}y=\sqrt{3}$

$\Rightarrow$     $\sqrt{3}y=x-\sqrt{3}$