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A ray of light along $x+\sqrt{3}y=\sqrt{3}$ gets reflected upon reaching x-axis , the equation of the reflected ray is

$y=x+\sqrt{3}$

$\sqrt{3}y=x-\sqrt{3}$

$y=\sqrt{3}x-\sqrt{3}$

$\sqrt{3}y=x-1$

Option B

Take any point B(0,1) on gives line, equation of AB'

$y-0= \frac{-1-0}{0-\sqrt{3}}(x-\sqrt{3})$

$\Rightarrow$ $-\sqrt{3}y=-x+\sqrt{3}$

$\Rightarrow$ $x-\sqrt{3}y=\sqrt{3}$

$\Rightarrow$ $\sqrt{3}y=x-\sqrt{3}$

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