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A gaseous hydrocarbon gives upon combustion 0.72 g of water and 3.08 g of CO₂. The empirical formula of the hydrocarbon is

A) $C_{2}H_{4}$

B) $C_{3}H_{4}$

C) $C_{6}H_{5}$

D) $C_{7}H_{8}$

Option D

18 g H₂O contains 2g H

$\therefore$ 0.72 g H₂O contains 0.08 g H

44fg CO₂ contains 12 gC

$\therefore$ 3.08 g CO₂ contains 0.84 gC

$\therefore$ C: H= $\frac{0.84}{12}:\frac{0.08}{1}$

=0.07:0.08

=7:8

$\therefore$ Emprical formula = C₇ H₈

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