Discussion Forum

A gaseous hydrocarbon gives upon combustion 0.72 g of water and 3.08 g of CO₂. The empirical formula of the hydrocarbon is 

Answer:

Explanation:

18 g H₂O  contains 2g H

 $\therefore$   0.72 g H₂O  contains  0.08 g H

   44fg CO₂  contains 12 gC

 $\therefore$    3.08 g CO₂ contains 0.84 gC

$\therefore$   C: H=  $\frac{0.84}{12}:\frac{0.08}{1}$

   =0.07:0.08

   =7:8

$\therefore$    Emprical  formula = C₇ H₈