Discussion Forum

A piston filled with 0.04 mole of an ideal gas expands reversibly from 50.0 ml to 375 ml at a constant temperature of 37.0° , As it does so, it absorbs 208 J of heat. The values of q and W for the process will be (R=8.314 J/mol K, ln 7.5 =2.01)

Answer:

Explanation:

The process is isothermal  expansion, hence

 Q=-W

 $\triangle E=0$

 $W=2.303 nRT log \frac{V_{2}}{V_{1}}$

   $=2.303\times0.04\times 8.314 \times310 \times log \frac{335}{50}$

  =-208 J

 Q=+208J

w= -208 J (expansion work)