Discussion Forum



1)

 Given,   $E^{0}_{Cr^{3+}/Cr}=-0.74 V$

 $E^{0}_{MnO_{4}^{-}/Mn^{2+}}=1.51 V$

$E^{0}_{Cr_{2}O_{7}^{2-}/Cr^{3+}}=1.33V$

$E^{0}_{{Cl}/Cl^{-}}=1.36V$

Based on the data given above strongest oxidising agent will be


A) Cl

B) $Cr^{3+}$

C) $Mn^{2+}$

D) $MnO_{4}^{-}$

Answer:

Option D

Explanation:

Higher the SRP,   better is oxidising agent. Among the given   $E_{MnO_{4}/Mn^{2+}}^{+}$ is highest, hence MnO4- is the strongest oxidising agent