1) Given, E0Cr3+/Cr=−0.74V E0MnO−4/Mn2+=1.51V E0Cr2O2−7/Cr3+=1.33V E0Cl/Cl−=1.36V Based on the data given above strongest oxidising agent will be A) Cl B) Cr3+ C) Mn2+ D) MnO−4 Answer: Option DExplanation:Higher the SRP, better is oxidising agent. Among the given E+MnO4/Mn2+ is highest, hence MnO4- is the strongest oxidising agent