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In a hydrogen-like atom electron makes the transition from an energy level with a quantum number n to another with a quantum number (n-1). If n>>1,  the frequency  of radiation emitted is proportional  to 

Answer:

Explanation:

$\triangle E=hv$

$v= \frac{\triangle E}{h}=k\left[\frac{1}{(n-1)^{2}}-\frac{1}{n^{2}}\right]$

$=\frac{k2n}{n^{2}(n-1)^{2}}$

$=\frac{2k}{n^{3}}\propto\frac{1}{n^{3}}$