1)

What is the minimum energy required to launch a satellite of mass m  from the surface of a planet of mass M and radius R in a circular orbit at an altitude of 2R?


A) $\frac{5GMm}{6R}$

B) $\frac{2GMm}{3R}$

C) $\frac{GMm}{2R}$

D) $\frac{GMm}{3R}$

Answer:

Option A

Explanation:

E= energy of satelite- energy of mass on the surface of plannar

    $=-\frac{GMm}{2r}-\left(-\frac{GMm}{R}\right)$

 Here, r= R+2R= 3R

 Substituting in about the equation we get,

                $E= \frac{5GMm}{6R}$