Discussion Forum

The reactions of Cl₂  gas with cold-dilute and hot -concentrated NaOH in water  give sodium salts of two (different)  oxoacids of chlorine, P and Q , respectively. The Cl₂ gas reacts with SO₂ gas , in the presence of charcoal, to give a product R. R reacts with white phosphorous to give a  compound s , on hydrolysis , s gives an oxoacid of phosphorous T.

P and Q respectively, are the sodium salts of 

Answer:

Explanation:

Plan 2NaOH +Cl₂  $\underrightarrow {cold}$    $NaCl+NaOCl+H_{2}O$

                                                                           P

$6NaOH+3Cl_{2}$  $\underrightarrow {hot}$   $5NaCl+NaClO_{3}+3H_{2}O$

                                                                                  Q

$HOCl$    $\underrightarrow {NaOH}$     $NaOCl$

hypochlorous                         P

acid

 $Cl_{2}+SO_{2}\rightarrow SO_{2}Cl_{2}$

                                           R

$10SO_{2}Cl_{2}+P_{4}\rightarrow 4PCl_{5}+10SO_{2}$

                                                  S

$PCl_{5}+4H_{2}O\rightarrow H_{3}PO_{4}+ 5HCl$

                                               T