Discussion Forum

In the nuclear transmutation   $^{9}_{4}Be+X\rightarrow ^{9}_{4}Be+Y$ (X,Y) is (are)

Answer:

Explanation:

Plan  

Atomic number same

 4+a=4+c

9+b=8+d

 If  $X= ^{0}_{0}\gamma$              a=0,  b=0

  $Y= ^{1}_{0}n$                    c=0, d=1

If   $X= ^{1}_{1}p$                  a=1, b=1

    $Y= ^{2}_{1}D$                   c=1, d=2

$^{9}_{4}Be+ ^{0}_{0}\gamma \rightarrow  ^{8}_{4}Be+ ^{1}_{0}n$

$^{9}_{4}Be+ ^{1}_{1}p \rightarrow  ^{8}_{4}Be+ ^{2}_{1}D$