Discussion Forum

After completion of the reactions (i and II), the organic compound (s) in reaction mixtures is (are )

Answer:

Explanation:

Plan  when acetone reacts with Br₂ in Basic medium , bromoform is formed

 Reaction I

 $CH_{3}COOCH_{3}(  1 mol, 1/3 mol )+3Br_{2}( 3 mol, 1 mol  )+4NaOH\rightarrow$

                                                  $ CH_{3}COONa+CHBr_{3}+3NaBr+3H_{2}O$

                                                                 (U)              (T)

 when CH₃COCH₃ are Br₂ are in equimolar quantity , all the Br₂ (limiting reactant)  is converted into desired products and 2/3 mole of CH₃COCH₃ remains unreacted, being in excess

 when acetone  reacts with Br₂ in acidic medium, there is monobromination of acetone

 Reaction II

$CH_{3}COCH_{3}+Br_{2}$   $\underrightarrow{CH_{3}COOH}$ 

                                                                            $CH_{3}COCH_{2}Br+HBr$ 

   1 mol                 1 mol                                         (p)

 CH₃COCH₃ and Br₂ react 1:1 mole ratio and (P) is formed

 in reaction I, (U) and (T) are formed and acetone (reactant) remains  unreacted

 In reaction II, (P) is formed