Discussion Forum

Match List I with List II  and select the correct answer using the codes given below the lists

Answer:

Explanation:

(p)$U=\frac{1}{2}kT$

 $\Rightarrow$      $[ML^{2}T^{-2}]=[k]K$

  $\Rightarrow$  $[K]= [ML^{2}T^{-2}K^{-1}]$

(q)    $F= \eta A\frac{dv}{dx}$

  $\Rightarrow [\eta]=\frac{[MLT^{-2}]}{[L^{2}LT^{-1}L^{-1}]}=[ML^{-1}T^{-1}]$

(r)   E=hv

  $\Rightarrow$    $[ML^{2}T^{2}]=[h][T^{-1}]$

$\Rightarrow$    $[h]= [ML^{2}T^{-1}]$

(s)   $\frac{dQ}{dt}=\frac{kA\triangle \theta}{l}$

 $[k]= \frac{[ML^{2}T^{-3}L]}{[L^{2}K]}=[MLT^{-3}K^{-1}]$