Answer:
Option C,D
Explanation:
For electrostatic field,
Ep= E1+E2
= $\frac{\rho}{3\epsilon_{0}}C_{1}P+\frac{(-\rho)}{3\epsilon_{0}}C_{1}P$
= $\frac{\rho}{3\epsilon_{0}}(C_{1}P+PC_{2})$
$E_{p}=\frac{\rho}{3\epsilon_{0}}C_{1}C_{2}$
For electrostatic potential: since the electric field is non zero so it is not equipotential