Answer:
Option B,D
Explanation:
At point P
If resultant electric field is zero then,
$\frac{KQ_{1}}{4R^{2}}=\frac{KQ_{2}}{8R^{3}}R$
$\frac{\rho_{1}}{\rho_{2}}=4$
At point Q
If resultant elecric field is zero then
$\frac{KQ_{1}}{4R^{2}}+\frac{KQ_{2}}{25R^{2}}=0$
$\frac{\rho_{1}}{\rho_{2}}=-\frac{32}{25}(\rho_{1}$ must be negative )