Answer:
Option A
Explanation:
$R_{1}=R_{1}+R_{2}=\left(\frac{l}{KA}\right)+\left(\frac{l}{2KA}\right)=\frac{3}{2}\left(\frac{l}{KA}\right)$
$\frac{1}{R_{II}}=\frac{1}{R_{1}}+\frac{1}{R_{2}}=\frac{KA}{l}+\frac{2KA}{l}$
or $ R_{II}=\frac{l}{3KA}=\frac{R_{1}}{4.5}$
since thermal resistance RII is 4.5 times less than thermal resistance R1
$\therefore$ $ t_{II}=\frac{t_{I}}{4.5}=2 s$