1) The value of the integral ∫π/2−π/2(x2+logπ−4π+4)cosxdx is A) 0 B) π22−4 C) π22+4 D) π22 Answer: Option BExplanation:∫π/2−π/2(x2+logπ−xπ+x)cosxdx As ∫a−af(x)dx=0 when f(-x) =-f(x) ∴ I=∫π/2−π/2x2cosxdx+0 = =2∫π/20(x2cosx)dx =2{(x2sinx)π/20−∫π/202x.sinxdx} =2[π24−2{−xcosx)π/20−∫π/201.(−cosx)dx}] =2[π24−2(sinx)π/20] =2[π24−2]=(π22−4)