Answer:
Option B
Explanation:
The concept involved the Distribution of objects into groups. Here, the student should be particular about objects and groups. i.e.,
Objects Groups
Distinct Distinct
Identical Identical
Distinct Identical
Identical Distinct
Description of Situation Here, 5 distinct balls are distributed amongst 3 persons so that each gets at least one ball.
i.e, Distinct $\rightarrow$ Distinct
so, we should make cases
Case I A B C
1 1 3
Case II A B C
1 2 2
sol. number of ways to distribute 5 balls is
$\left(^{5}C_{1}.^{4}C_{3}.^{3}C_{3} \times \frac{3!}{2!}\right)+\left(^{5}C_{1}.^{4}C_{2}.^{2}C_{2} \times \frac{3!}{2!}\right)$
=60+90
=150
