Answer:
Option A
Explanation:
Bleaching powder is $Ca(OCl)Cl.$ Therefore, the oxoacid whose salt is present in bleaching powder is HOCl. Anhydride of HOCl is $-Cl_{2}O$ as $2HOCl \rightarrow Cl_{2}O+H_{2}O$
[Note The oxidation number of element in anhydride and oxoacid remains the same]