Answer:
Option C
Explanation:
According to Bohr's model
$mvr=\frac{nh}{2\pi|}$
$\Rightarrow$ $(mv)^{2}=\frac{n^{2}h^{2}}{4\pi^{2}r^{2}}$
$\Rightarrow$ $KE=\frac{1}{2}mv^{2}=\frac{n^{2}h^{2}}{8\pi^{2}r^{2}m}$......(i)
Also Bohr's radius for H-atom is $r=n^{2}a_{0}$
Substiuting 'r' in equation (i) gives
$KE= \frac{h^{2}}{8 \pi^{2}n^{2}a_{0}^{2}m}$
wher n=2,
KE=$\frac{h^{2}}{32 \pi^{2}m a_{0}^{2}}$