Answer:
Option A,B,C
Explanation:
Resultant of 2K and 2K (at $120^{0}C)$ is also 2K towards 4K. Therefore , net electric field is 6K
(b) $V_{0}=\frac{1}{4 \pi \epsilon_{0}}$
=$ \frac{1}{4 \pi \epsilon_{0} L} (q_{A}+.....+q_{E})$
=0
Because $q_{A}+q_{B}+q_{C}+q_{D}+q_{E}+q_{F}=0$
(c) only line PR , potential is same (=0)