Answer:
Option B
Explanation:
Area of the given loop is
A=(area of two circles of radius $\frac{a}{2}$ and area ofa square of side a )
$=2 \pi\left(\frac{a}{2}\right)^{2}+a^{2}$
$=\left(\frac{\pi}{2}+1\right)a^{2}$
$|M|=IA=\left(\frac{\pi}{2}+1\right)a^{2}I$
From screw law direction of M is outwards or in positive z-direction
$\therefore$ M=$\left(\frac{\pi}{2}+1\right)a^{2}Ik$