Answer:
Option C,D
Explanation:
(a) and (b)
The magnetic field will rotate the particle in a circular path {in x-z plane or perpendicular to B). The electric field will exert a constant force on the particle in Positive y-direction. Therefore, the resultant path is neither purely circular nor helical or the options (a) and (b) both are wrong
(c)
$v_{\perp}$ and B will rotate the particle in a circular path in the x- z plane (or perpendicular to B). Further $v_{||}$ and E will move the panicle (with increasing speed) along the positive y-axis (or along the axis of the above circular path). Therefore, the resultant path is helical with increasing pitch, along the y-axis (or along B and E). Therefore option (c) is correct.
(d)
Magnetic force is zero, as $\theta$ between B and v is zero. But electric force will act in the y-direction. Therefore. motion is 1-D and uniformly accelerated (towards positive y-direction).