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1)

lf z is any complex number satisfying|z32i|2,  then the maximum value of |2z-6+5i| is 


A) 4

B) 5

C) 6

D) 7

Answer:

Option B

Explanation:

Given ,|z32i|2....(i)

 To find  minimum of |2z-6+5i|

 or  2|z3+52i|

 Using triangle inequality

 i.e, ||z1||z2|||z1+z2|

     |z3+52i|

 =|z32i+2i+52i|

 =|(z32i)+92i||z32i|92|

 |292|52|z3+52i|52

   or    |2z6+5i|5