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1)

Let α and β  be the roots of x26x2=0 with α>β , if an=αnβn for 1, then the value of a102a82a9 is 


A) 1

B) 2

C) 3

D) 4

Answer:

Option C

Explanation:

a102a82a9=(α10β10)2(α8β8)2(α9β9)

=α8(α22)β8(β22)2(α9β9)

 [   is root of  x26x2=0

                                            α22=6α]

Also,β is the root of x26x2=0

  β22=6β

=α8(6α)β8(6β)2(α9β9)=6(α9β9)2(α9β9)=3