Discussion Forum

Among the following, the number of compounds than can react with  $PCl_{5}$ to  give $POCl_{3}, $ is $O_{2}$ , $CO_{2},SO_{2},H_{2}O, H_{2}SO_{4}, P_{4}O_{10}$

Answer:

Explanation:

 $PCl_{3}$ produces $POCl_{3}$  with the following reagents

    $PCl_{5}+SO_{2} \rightarrow  POCl_{3}+SOCl_{2}$

  $PCl_{5}+H_{2}O \rightarrow   POCl_{3}+2HCl$

$ PCl_{5}+H_{2}SO_{4} \rightarrow   SO_{2}Cl_{2}+2POCl_{3}+2HCl$

  $6 PCl_{5}+P_{4}O_{10} \rightarrow  10 POCl_{3}$