Answer:
Option D
Explanation:
As $AgNO_{3}$ is added to the solution, KCI will be displayed according to the following reaction
$AgNO_{3}(aq) +KCl(aq) \rightarrow AgCl(s)+KNO_{3}(aq)$
For every mole of KCI displaced from the solution, one mole of KNO3 comes into the solution resulting in almost constant conductivity. As the end point is reached, added AgNO3 remain in solution increasing ionic concenkation, hence conductivity increases