Discussion Forum

Bombardment of aluminium by α-particle leads to its artificial disintegration in two ways, (i) and (ii) as shown. Products X, Y and Z respectively are

Answer:

Explanation:

(i) $^{27}_{13}Al+^{4}_{2}He (\alpha) \rightarrow ^{30}_{14}Si+^{1}_{1}X\Rightarrow X$  is proton $^{1}_{1}H$

(ii)$^{27}_{13}Al+^{4}_{2}He (\alpha) \rightarrow ^{30}_{15}P+^{1}_{0}Y\Rightarrow Y$  is neutron $^{1}_{0}n$

  $^{30}_{15}P \rightarrow ^{30}_{14}Si+^{0}_{1}Z$

$\Rightarrow$       Z is positron  $_{+1}^{0} e$