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1)

Two solid spheres A and B of equal volumes but of different densities dA and dB are connected by a string. They are fully immersed in a fluid of density dF. They get arranged into an equilibrium state as shown in the figure with a tension in the string. The arrangement is possible only if

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A) dA < dF

B) dB > dF

C) dA > dF

D) dA +dB =2 dF

Answer:

Option A,B,D

Explanation:

30112021366_t2.PNG

  F= Upthrust=  VdFg

Equilibrium of A

 VdFg=T+WA

                   =T+VdAg

 Equilibrium of B

  T+VdFg=VdBg

Adding Eqs. (i) and (ii), we get

 2dF=dA+dB

  Option(d) is correct

From Eq. (i), we can see that

  dF>dA       [as T >0]

 Option (a) is correct

From Eq. (ii) we can see that

 dB>dF

 Option (a) is correct.

 Correct options are (a), (b) and (d)