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1)

Four-point charges, each of +q are rigidly fixed at the four corners of a square planar soap film of side a. The surface tension, of the soap film is γ . The system of charges and planar film are in equilibrium and, a=k[q2γ]1/N. where k is a constant. Then N is 


A) 4

B) 5

C) 3

D) 2

Answer:

Option C

Explanation:

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F1= Net electrostatic force on anyone charge due to rest of three charges

   =14πϵ0q2a2(2+12)

 F2= surface tension force =γa

 If we see the equilibrium of line BC, 

then 2F1cos450=F2

 or   2F1=F2

 or  14πϵ0q2a2(2+12)=γa

  a^{3}= \frac{1}{4 \pi \epsilon_{0}}(2+\frac{1}{\sqrt{2}})\frac{q^{2}}{\gamma}

 or    a= [\frac{1}{4 \pi \epsilon_{0}}(2+\frac{1}{\sqrt{2}})]^\frac{1}{3}[\frac{q^{2}}{\gamma}]^\frac{1}{3}

   =k\left[\frac{q^{2}}{\gamma}\right]^{1/3}

 where  , k=\left\{\frac{1}{4 \pi \epsilon_{0}}(2+\frac{1}{\sqrt{2}})\right\}^{1/3}

 Therefore    ,N=3

 Answer is 3