Answer:
Option C
Explanation:
Number of candidates clearing the exam from State D in
2008 → $\left(1.83\times\frac{60}{100}\right) lakhs $
= $\frac{(1.83\times3)}{5} lakhs $
= $\frac{5.49}{5} lakhs = 1.10 lakhs$
2009 → $\left(2.01\times\frac{56}{100}\right) lakhs$
= $\frac{(2.01\times14)}{25} lakhs$
= $\frac{28.14}{25} lakhs = 1.12 lakhs$
In rest of the years it is clearly less. So, it is maximum in the year 2009.
