Answer:
Option B
Explanation:
Average number of students qualified from C and D
= $\frac{1}{2}$(2250+2000) = $\frac{4250}{2}$ = 2125
Average number of students appeared from C and D
= $\frac{1}{2}$(3250+2500) = $\frac{5750}{2}$ = 2875
Required% = $\left(\frac{2125}{2875}\times100\right)$%
= $\frac{1700}{23}$% = 73.91%