1)

Three Spherical balls of radius 1 cm,2 cm and 3 cmmelted to form a single spherical ball.In the process, the material loss was 25%.What would be the radius of the new ball?


A) 4.5 cm

B) 3 cm

C) 3.6 cm

D) 4 cm

Answer:

Option B

Explanation:

Volume of sphere = $\frac{4}{3}\pi r^{3}$

Volume of 3 small spherical balls=$\frac{4}{3} \pi (1^{3}+2^{3}+3^{3}$

                                               =$\frac{4}{3}\pi (1+8+27)$$=\frac{4}{3}\pi \times 36$ $=48\pi$

Material loss =25%

$\therefore$ Volume of the single spherical ball $=\frac{48\pi \times 75}{100}$

$\Rightarrow \frac{48\pi \times 3}{4}= 36\pi$

$=\frac{4}{3}\pi r^{3}=36\pi$ 

$\Rightarrow r^{3}=\frac{36\times 3}{4}=27$ $r=3 cm$