Answer:
Option E
Explanation:
I. $(X+Y)$'s $1$ day's work $=\frac{1}{6}$.
II. $(Y+Z)$'s $1$ day's work $=\frac{4}{15}$.
III. $(X+Z)$'s $1$ day's work $=\frac{3}{10}$.
Adding, we get $2(X+Y+Z)$'s $1$ day's work $=\left(\frac{1}{6}+\frac{4}{15}+\frac{3}{10}\right)$ $=\frac{22}{30}$.
$\Rightarrow$ $(X+Y+Z)$'s $1$ day's work $=\left(\frac{1}{2}\times\frac{22}{30}\right)$ $=\frac{11}{30}$.
Thus, $X$, $Y$ and $Z$ together can finish the work in $\frac{30}{11}$ days.
Hence I, II and III are necessary to answer the question.
$\therefore$ Correct answer is (E).