Discussion Forum

A and B together can complete a work in 3 days. They start together but after 2 days, B left the work. If the work is completed after 2 more days, B alone can do the work in

Answer:

Explanation:

$(A+B)$'s 2 days work = $\left(\frac{1}{3}\times 2\right)$ $=\frac{2}{3}$.

Remaining work $=\left(1-\frac{2}{3}\right)$ $=\frac{1}{3}$.

Now, $\frac{1}{3}$ work is done by $A$ in 2 days.

Whole work will be done by $A$ in $(2\times 3)$ = 6 days.