Discussion Forum

A can finish a work in 18 days and B can do the same work in 15 days. B worked for 10 days and left the job. In how many days, A alone can finish the remaining work ?

Answer:

Explanation:

$B$'s 10 days' work $=\frac{1}{15}\times 10$ $=\frac{2}{3}$

Remaining work $=\left(1-\frac{2}{3}\right)$ $=\frac{1}{3}$

Now, $\frac{1}{18}$ work is done by $A$ in $1$ day.

$\frac{1}{3}$ work is done by $A$ in $18\times\frac{1}{3}$ = 6 days.