Answer:
Option E
Explanation:
Let the usual speed of the train be x kmph.
Time taken to cover 150 km at usual speed =150x hrs.
I. Time taken at increased speed =150x+25 hrs.
II. 150x−150(x+25) =3060.
⇔ 1x−1(x+25) =1300
⇔ [(x+25)−x]×3000 =x(x+25)
⇔ x2+25x−7500=0
⇔ (x+100)(x−75)=0
⇔x=75.
Thus, I and II together give the answer.
∴ Correct answer is (E).