Answer:
Option E
Explanation:
Let the usual speed of the train be $x$ kmph.
Time taken to cover 150 km at usual speed $=\frac{150}{x}$ hrs.
I. Time taken at increased speed $=\frac{150}{x+25}$ hrs.
II. $\frac{150}{x}-\frac{150}{(x+25)}$ $=\frac{30}{60}$.
$\Leftrightarrow$ $\frac{1}{x}-\frac{1}{(x+25)}$ $=\frac{1}{300}$
$\Leftrightarrow$ $\left[(x+25)-x\right]\times 3000$ $=x(x+25)$
$\Leftrightarrow$ $x^{2}+25x-7500=0$
$\Leftrightarrow$ $(x+100)(x-75)=0$
$\Leftrightarrow x=75$.
Thus, I and II together give the answer.
$\therefore$ Correct answer is (E).