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Walking at $\frac{5}{6}$ of its usual speed, a train is 10 minutes too late. Find its usual time to cover the journey.

Answer:

Explanation:

New speed $=\frac{5}{6}$ of the usual speed

New time taken $=\frac{6}{5}$ of the usual time

so, $\frac{6}{5}$ of the usual time - usual time = 10 mn.

$\Rightarrow$ $\frac{1}{5}$ of the usual time = 10 min $\Rightarrow$ usual time = 50 min.