Discussion Forum

Find the units digit in $(264)^{102}+(264)^{103}$

Answer:

Explanation:

Required units digit=units digit in $(4)^{102}+(4)^{103}$

$4^{2}$ gives unit digit 6

$(4)^{102}$ gives unit digit 6

$(4)^{103}$ gives unit digit of $6\times 4=4$ 

Unit's digit in (264)^{102} +(264)^{103}=6+4=0