Discussion Forum

Find the total number of prime factors in the expression$4^{11}\times 7^{5}\times 11^{2}$?

Answer:

Explanation:

$4^{11}\times 7^{5}\times 11^{2}=(2^{2})^{11}\times 7^{5}\times 11^{2}$$=2^{22}\times 7^{5}\times 11^{2}$

Total number of prime factors =22+5+2=29