Answer:
Option B
Explanation:
(216)35×(2500)25×(300)15= (33×23)35×(54×22)25×(52×22×3)15 =3[3×35]×2[3×35]×5[4×25]×2[2×25]×5[2×15]×2[2×15]×315 =395×295×585×245×525×225×315 =3[95+15]×2[95+45+25]×5[85+25] =32×23×52 Hence, the number of prime factors = (2+3+2)=7