Discussion Forum

If $2^{2n-1}=\frac{1}{8^{n-3}}$, then the value of n is:

Answer:

Explanation:

$2^{2n-1}=\frac{1}{8^{n-3}}$ $\Leftrightarrow 2^{2n-1}=\frac{1}{\left(2^{3}\right)^{n-3}}$ $=\frac{1}{2^{3}\left(^{n-3}\right)}$ $=\frac{1}{2\left(^{3n-9}\right)}$ $=2^\left({9-3n}\right)$ $\Leftrightarrow 2n-1$ $=9-3n$ $\Leftrightarrow 5n=10$ $\Leftrightarrow n=2$